68=4(5x2)

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Solution for 68=4(5x2) equation:



68=4(5x^2)
We move all terms to the left:
68-(4(5x^2))=0
determiningTheFunctionDomain -45x^2+68=0
a = -45; b = 0; c = +68;
Δ = b2-4ac
Δ = 02-4·(-45)·68
Δ = 12240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12240}=\sqrt{144*85}=\sqrt{144}*\sqrt{85}=12\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{85}}{2*-45}=\frac{0-12\sqrt{85}}{-90} =-\frac{12\sqrt{85}}{-90} =-\frac{2\sqrt{85}}{-15} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{85}}{2*-45}=\frac{0+12\sqrt{85}}{-90} =\frac{12\sqrt{85}}{-90} =\frac{2\sqrt{85}}{-15} $

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