2/3(7t-1)+2/3t=17/3-t

Solution for 2/3(7t-1)+2/3t=17/3-t equation:

2/3(7t-1)+2/3t=17/3-t

We move all terms to the left:

2/3(7t-1)+2/3t-(17/3-t)=0


Domain of the equation: 3(7t-1)!=0

t∈R



Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R



Domain of the equation: 3-t)!=0

We move all terms containing t to the left, all other terms to the right

-t)!=-3

t!=-3/1

t!=-3

t∈R


We add all the numbers together, and all the variables

2/3(7t-1)+2/3t-(-1t+17/3)=0

We get rid of parentheses

2/3(7t-1)+2/3t+1t-17/3=0

We calculate fractions


1t+6t/(3(7t-1)*3t*3)+(6t7/(3(7t-1)*3t*3)=0


We calculate terms in parentheses: +(6t7/(3(7t-1)*3t*3), so:

6t7/(3(7t-1)*3t*3

We multiply all the terms by the denominator


6t7

We add all the numbers together, and all the variables

6t^7

We do not support etpression: t^7