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68=1/5(20a+50)+2
We move all terms to the left:
68-(1/5(20a+50)+2)=0
Domain of the equation: 5(20a+50)+2)!=0We multiply all the terms by the denominator
a∈R
-(1+68*5(20a+50)+2)=0
We calculate terms in parentheses: -(1+68*5(20a+50)+2), so:We add all the numbers together, and all the variables
1+68*5(20a+50)+2
determiningTheFunctionDomain 68*5(20a+50)+1+2
We add all the numbers together, and all the variables
68*5(20a+50)+3
Wy multiply elements
340a(2+3
Back to the equation:
-(340a(2+3)
-(340a5=0
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