(3x-11)+(6x-10)+x=180

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Solution for (3x-11)+(6x-10)+x=180 equation: 



(3x-11)+(6x-10)+x=180

We move all terms to the left:

(3x-11)+(6x-10)+x-(180)=0

We add all the numbers together, and all the variables

x+(3x-11)+(6x-10)-180=0

We get rid of parentheses

x+3x+6x-11-10-180=0

We add all the numbers together, and all the variables

10x-201=0

We move all terms containing x to the left, all other terms to the right

10x=201

x=201/10

x=20+1/10

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