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66x(x+7)=122
We move all terms to the left:
66x(x+7)-(122)=0
We multiply parentheses
66x^2+462x-122=0
a = 66; b = 462; c = -122;
Δ = b2-4ac
Δ = 4622-4·66·(-122)
Δ = 245652
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{245652}=\sqrt{4*61413}=\sqrt{4}*\sqrt{61413}=2\sqrt{61413}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(462)-2\sqrt{61413}}{2*66}=\frac{-462-2\sqrt{61413}}{132} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(462)+2\sqrt{61413}}{2*66}=\frac{-462+2\sqrt{61413}}{132} $
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