2(2t-3)=6+t

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Solution for 2(2t-3)=6+t equation: 



2(2t-3)=6+t

We move all terms to the left:

2(2t-3)-(6+t)=0

We add all the numbers together, and all the variables

2(2t-3)-(t+6)=0

We multiply parentheses

4t-(t+6)-6=0

We get rid of parentheses

4t-t-6-6=0

We add all the numbers together, and all the variables

3t-12=0

We move all terms containing t to the left, all other terms to the right

3t=12

t=12/3

t=4

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