668=((20x+4)/3)

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Solution for 668=((20x+4)/3) equation: 



668=((20x+4)/3)

We move all terms to the left:

668-(((20x+4)/3))=0

We multiply all the terms by the denominator


-(((20x+4)+668*3))=0



We calculate terms in parentheses: -(((20x+4)+668*3)), so:

((20x+4)+668*3)



We calculate terms in parentheses: +((20x+4)+668*3), so:

(20x+4)+668*3

We add all the numbers together, and all the variables

(20x+4)+2004

We get rid of parentheses

20x+4+2004

We add all the numbers together, and all the variables

20x+2008

Back to the equation:

+(20x+2008)



We get rid of parentheses

20x+2008

Back to the equation:

-(20x+2008)



We get rid of parentheses

-20x-2008=0

We move all terms containing x to the left, all other terms to the right

-20x=2008

x=2008/-20

x=-100+2/5

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