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(11v-12)(12+11v)=0
We add all the numbers together, and all the variables
(11v-12)(11v+12)=0
We use the square of the difference formula
121v^2-144=0
a = 121; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·121·(-144)
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{69696}=264$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-264}{2*121}=\frac{-264}{242} =-1+1/11 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+264}{2*121}=\frac{264}{242} =1+1/11 $
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