65y=32(2y+13)

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Solution for 65y=32(2y+13) equation: 



65y=32(2y+13)

We move all terms to the left:

65y-(32(2y+13))=0



We calculate terms in parentheses: -(32(2y+13)), so:

32(2y+13)

We multiply parentheses

64y+416

Back to the equation:

-(64y+416)



We get rid of parentheses

65y-64y-416=0

We add all the numbers together, and all the variables

y-416=0

We move all terms containing y to the left, all other terms to the right

y=416

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