(x+7)(36x-9)=2

Solution for (x+7)(36x-9)=2 equation:

(x+7)(36x-9)=2

We move all terms to the left:

(x+7)(36x-9)-(2)=0

We multiply parentheses ..

(+36x^2-9x+252x-63)-2=0

We get rid of parentheses

36x^2-9x+252x-63-2=0

We add all the numbers together, and all the variables

36x^2+243x-65=0

a = 36; b = 243; c = -65;
Δ = b2-4ac
Δ = 2432-4·36·(-65)
Δ = 68409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68409}=\sqrt{9*7601}=\sqrt{9}*\sqrt{7601}=3\sqrt{7601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(243)-3\sqrt{7601}}{2*36}=\frac{-243-3\sqrt{7601}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(243)+3\sqrt{7601}}{2*36}=\frac{-243+3\sqrt{7601}}{72}
$