64=4(4x+3)-6x

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Solution for 64=4(4x+3)-6x equation: 



64=4(4x+3)-6x

We move all terms to the left:

64-(4(4x+3)-6x)=0



We calculate terms in parentheses: -(4(4x+3)-6x), so:

4(4x+3)-6x

We add all the numbers together, and all the variables

-6x+4(4x+3)

We multiply parentheses

-6x+16x+12

We add all the numbers together, and all the variables

10x+12

Back to the equation:

-(10x+12)



We get rid of parentheses

-10x-12+64=0

We add all the numbers together, and all the variables

-10x+52=0

We move all terms containing x to the left, all other terms to the right

-10x=-52

x=-52/-10

x=5+1/5

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