64=4(1+5b)

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Solution for 64=4(1+5b) equation: 



64=4(1+5b)

We move all terms to the left:

64-(4(1+5b))=0

We add all the numbers together, and all the variables

-(4(5b+1))+64=0



We calculate terms in parentheses: -(4(5b+1)), so:

4(5b+1)

We multiply parentheses

20b+4

Back to the equation:

-(20b+4)



We get rid of parentheses

-20b-4+64=0

We add all the numbers together, and all the variables

-20b+60=0

We move all terms containing b to the left, all other terms to the right

-20b=-60

b=-60/-20

b=+3

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