64=(x-5)/(2x+5)

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Solution for 64=(x-5)/(2x+5) equation: 



64=(x-5)/(2x+5)

We move all terms to the left:

64-((x-5)/(2x+5))=0



Domain of the equation: (2x+5))!=0

x∈R



We multiply all the terms by the denominator


-((x-5)+64*(2x+5))=0



We calculate terms in parentheses: -((x-5)+64*(2x+5)), so:

(x-5)+64*(2x+5)

We multiply parentheses

(x-5)+128x+320

We get rid of parentheses

x+128x-5+320

We add all the numbers together, and all the variables

129x+315

Back to the equation:

-(129x+315)



We get rid of parentheses

-129x-315=0

We move all terms containing x to the left, all other terms to the right

-129x=315

x=315/-129

x=-2+19/43

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