3(y+2)+y=3(y-1)+6

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Solution for 3(y+2)+y=3(y-1)+6 equation: 



3(y+2)+y=3(y-1)+6

We move all terms to the left:

3(y+2)+y-(3(y-1)+6)=0

We add all the numbers together, and all the variables

y+3(y+2)-(3(y-1)+6)=0

We multiply parentheses

y+3y-(3(y-1)+6)+6=0



We calculate terms in parentheses: -(3(y-1)+6), so:

3(y-1)+6

We multiply parentheses

3y-3+6

We add all the numbers together, and all the variables

3y+3

Back to the equation:

-(3y+3)



We add all the numbers together, and all the variables

4y-(3y+3)+6=0

We get rid of parentheses

4y-3y-3+6=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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