5+2(2y-6)=-3(4y-1)+4y

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Solution for 5+2(2y-6)=-3(4y-1)+4y equation: 



5+2(2y-6)=-3(4y-1)+4y

We move all terms to the left:

5+2(2y-6)-(-3(4y-1)+4y)=0

We multiply parentheses

4y-(-3(4y-1)+4y)-12+5=0



We calculate terms in parentheses: -(-3(4y-1)+4y), so:

-3(4y-1)+4y

We add all the numbers together, and all the variables

4y-3(4y-1)

We multiply parentheses

4y-12y+3

We add all the numbers together, and all the variables

-8y+3

Back to the equation:

-(-8y+3)



We add all the numbers together, and all the variables

4y-(-8y+3)-7=0

We get rid of parentheses

4y+8y-3-7=0

We add all the numbers together, and all the variables

12y-10=0

We move all terms containing y to the left, all other terms to the right

12y=10

y=10/12

y=5/6

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