64+225=c2

Solution for 64+225=c2 equation:

64+225=c2

We move all terms to the left:

64+225-(c2)=0

We add all the numbers together, and all the variables

-1c^2+289=0

a = -1; b = 0; c = +289;
Δ = b2-4ac
Δ = 02-4·(-1)·289
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34}{2*-1}=\frac{-34}{-2}
=+17
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34}{2*-1}=\frac{34}{-2}
=-17
$