4p(2)+9p-18=0

Solution for 4p(2)+9p-18=0 equation:

4p(2)+9p-18=0

We add all the numbers together, and all the variables

4p^2+9p-18=0

a = 4; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·4·(-18)
Δ = 369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{369}=\sqrt{9*41}=\sqrt{9}*\sqrt{41}=3\sqrt{41}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{41}}{2*4}=\frac{-9-3\sqrt{41}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{41}}{2*4}=\frac{-9+3\sqrt{41}}{8}
$