64+(4(3y+2)=180)

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Solution for 64+(4(3y+2)=180) equation:



64+(4(3y+2)=180)
We move all terms to the left:
64+(4(3y+2)-(180))=0
We calculate terms in parentheses: +(4(3y+2)-180), so:
4(3y+2)-180
We multiply parentheses
12y+8-180
We add all the numbers together, and all the variables
12y-172
Back to the equation:
+(12y-172)
We get rid of parentheses
12y-172+64=0
We add all the numbers together, and all the variables
12y-108=0
We move all terms containing y to the left, all other terms to the right
12y=108
y=108/12
y=9

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