4y-2-2(y+1)=y+3

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Solution for 4y-2-2(y+1)=y+3 equation: 



4y-2-2(y+1)=y+3

We move all terms to the left:

4y-2-2(y+1)-(y+3)=0

We multiply parentheses

4y-2y-(y+3)-2-2=0

We get rid of parentheses

4y-2y-y-3-2-2=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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