63=3x+3(3x-19)

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Solution for 63=3x+3(3x-19) equation: 



63=3x+3(3x-19)

We move all terms to the left:

63-(3x+3(3x-19))=0



We calculate terms in parentheses: -(3x+3(3x-19)), so:

3x+3(3x-19)

We multiply parentheses

3x+9x-57

We add all the numbers together, and all the variables

12x-57

Back to the equation:

-(12x-57)



We get rid of parentheses

-12x+57+63=0

We add all the numbers together, and all the variables

-12x+120=0

We move all terms containing x to the left, all other terms to the right

-12x=-120

x=-120/-12

x=+10

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