X2-24+48y=0

Solution for X2-24+48y=0 equation:

X2-24+48X=0

We add all the numbers together, and all the variables

X^2+48X-24=0

a = 1; b = 48; c = -24;
Δ = b2-4ac
Δ = 482-4·1·(-24)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-20\sqrt{6}}{2*1}=\frac{-48-20\sqrt{6}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+20\sqrt{6}}{2*1}=\frac{-48+20\sqrt{6}}{2}
$