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62=5-3(1-2n)
We move all terms to the left:
62-(5-3(1-2n))=0
We add all the numbers together, and all the variables
-(5-3(-2n+1))+62=0
We calculate terms in parentheses: -(5-3(-2n+1)), so:We get rid of parentheses
5-3(-2n+1)
determiningTheFunctionDomain -3(-2n+1)+5
We multiply parentheses
6n-3+5
We add all the numbers together, and all the variables
6n+2
Back to the equation:
-(6n+2)
-6n-2+62=0
We add all the numbers together, and all the variables
-6n+60=0
We move all terms containing n to the left, all other terms to the right
-6n=-60
n=-60/-6
n=+10
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