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60x-2400/60x=0.3
We move all terms to the left:
60x-2400/60x-(0.3)=0
Domain of the equation: 60x!=0We add all the numbers together, and all the variables
x!=0/60
x!=0
x∈R
60x-2400/60x-0.3=0
We multiply all the terms by the denominator
60x*60x-(0.3)*60x-2400=0
We multiply parentheses
60x*60x-18x-2400=0
Wy multiply elements
3600x^2-18x-2400=0
a = 3600; b = -18; c = -2400;
Δ = b2-4ac
Δ = -182-4·3600·(-2400)
Δ = 34560324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{34560324}=\sqrt{36*960009}=\sqrt{36}*\sqrt{960009}=6\sqrt{960009}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{960009}}{2*3600}=\frac{18-6\sqrt{960009}}{7200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{960009}}{2*3600}=\frac{18+6\sqrt{960009}}{7200} $
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