x(7x+1)=(7x+1)(x-2)

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Solution for x(7x+1)=(7x+1)(x-2) equation: 



x(7x+1)=(7x+1)(x-2)

We move all terms to the left:

x(7x+1)-((7x+1)(x-2))=0

We multiply parentheses

7x^2+x-((7x+1)(x-2))=0

We multiply parentheses ..

7x^2-((+7x^2-14x+x-2))+x=0



We calculate terms in parentheses: -((+7x^2-14x+x-2)), so:

(+7x^2-14x+x-2)

We get rid of parentheses

7x^2-14x+x-2

We add all the numbers together, and all the variables

7x^2-13x-2

Back to the equation:

-(7x^2-13x-2)



We add all the numbers together, and all the variables

7x^2+x-(7x^2-13x-2)=0

We get rid of parentheses

7x^2-7x^2+x+13x+2=0

We add all the numbers together, and all the variables

14x+2=0

We move all terms containing x to the left, all other terms to the right

14x=-2

x=-2/14

x=-1/7

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