60=(x+20)3x

Solution for 60=(x+20)3x equation:

60=(x+20)3x

We move all terms to the left:

60-((x+20)3x)=0


We calculate terms in parentheses: -((x+20)3x), so:

(x+20)3x

We multiply parentheses

3x^2+60x

Back to the equation:

-(3x^2+60x)


We get rid of parentheses

-3x^2-60x+60=0

a = -3; b = -60; c = +60;
Δ = b2-4ac
Δ = -602-4·(-3)·60
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12\sqrt{30}}{2*-3}=\frac{60-12\sqrt{30}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12\sqrt{30}}{2*-3}=\frac{60+12\sqrt{30}}{-6}
$