2(4c+3)+4=3c-(2c+4)

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Solution for 2(4c+3)+4=3c-(2c+4) equation: 



2(4c+3)+4=3c-(2c+4)

We move all terms to the left:

2(4c+3)+4-(3c-(2c+4))=0

We multiply parentheses

8c-(3c-(2c+4))+6+4=0



We calculate terms in parentheses: -(3c-(2c+4)), so:

3c-(2c+4)

We get rid of parentheses

3c-2c-4

We add all the numbers together, and all the variables

c-4

Back to the equation:

-(c-4)



We add all the numbers together, and all the variables

8c-(c-4)+10=0

We get rid of parentheses

8c-c+4+10=0

We add all the numbers together, and all the variables

7c+14=0

We move all terms containing c to the left, all other terms to the right

7c=-14

c=-14/7

c=-2

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