600n=800(n-3/4

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Solution for 600n=800(n-3/4 equation: 



600n=800(n-3/4

We move all terms to the left:

600n-(800(n-3/4)=0

We add all the numbers together, and all the variables

600n-(800(+n-3/4)=0

We multiply all the terms by the denominator


600n*4)-(800(+n-3=0

Wy multiply elements

2400n^2=0

a = 2400; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2400·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4800}=0$

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