2x-4(x-4)=8+4x+6

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Solution for 2x-4(x-4)=8+4x+6 equation: 



2x-4(x-4)=8+4x+6

We move all terms to the left:

2x-4(x-4)-(8+4x+6)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(4x+14)=0

We multiply parentheses

2x-4x-(4x+14)+16=0

We get rid of parentheses

2x-4x-4x-14+16=0

We add all the numbers together, and all the variables

-6x+2=0

We move all terms containing x to the left, all other terms to the right

-6x=-2

x=-2/-6

x=1/3

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