8/(x+1)-5/2=8/(3x+3)

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Solution for 8/(x+1)-5/2=8/(3x+3) equation: 



8/(x+1)-5/2=8/(3x+3)

We move all terms to the left:

8/(x+1)-5/2-(8/(3x+3))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (3x+3))!=0

x∈R



We calculate fractions


48x/((x+1)*(3x+3))*2)+(-(8*(x+1)*2)/((x+1)*(3x+3))*2)+(-5*(x+1)*(3x+3)))/((x+1)*(3x+3))*2)=0

We add all the numbers together, and all the variables

48x/((x+1)*(3x+3))*2)+(-(8*(x+1)*2)/((x+1)*(3x+3))*2)+(-5*(x+1)*(3x+3)))/((x+1)*(3x=0

We calculate fractions


1)*(3x+(48x-(8*(x+1)*2)*(x/(((x+1)*(3x+3))*2)+(*(x+(-5*(x+1)*(3x+3)))*((x+1)*3x/(((x+1)*(3x+3))*2)+(*(x=0

We can not solve this equation

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