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600=3(x-6)(2.9x-6)
We move all terms to the left:
600-(3(x-6)(2.9x-6))=0
We multiply parentheses ..
-(3(+2x^2-6x-12x+36))+600=0
We calculate terms in parentheses: -(3(+2x^2-6x-12x+36)), so:We get rid of parentheses
3(+2x^2-6x-12x+36)
We multiply parentheses
6x^2-18x-36x+108
We add all the numbers together, and all the variables
6x^2-54x+108
Back to the equation:
-(6x^2-54x+108)
-6x^2+54x-108+600=0
We add all the numbers together, and all the variables
-6x^2+54x+492=0
a = -6; b = 54; c = +492;
Δ = b2-4ac
Δ = 542-4·(-6)·492
Δ = 14724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14724}=\sqrt{36*409}=\sqrt{36}*\sqrt{409}=6\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{409}}{2*-6}=\frac{-54-6\sqrt{409}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{409}}{2*-6}=\frac{-54+6\sqrt{409}}{-12} $
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