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12=(-3)/(5)y
We move all terms to the left:
12-((-3)/(5)y)=0
Domain of the equation: 5y)!=0We multiply all the terms by the denominator
y!=0/1
y!=0
y∈R
-((-3)+12*5y)=0
We calculate terms in parentheses: -((-3)+12*5y), so:We get rid of parentheses
(-3)+12*5y
determiningTheFunctionDomain 12*5y+(-3)
We add all the numbers together, and all the variables
12*5y-3
Wy multiply elements
60y-3
Back to the equation:
-(60y-3)
-60y+3=0
We move all terms containing y to the left, all other terms to the right
-60y=-3
y=-3/-60
y=1/20
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