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60-(5x+6)=2(x+3)+x
We move all terms to the left:
60-(5x+6)-(2(x+3)+x)=0
We get rid of parentheses
-5x-(2(x+3)+x)-6+60=0
We calculate terms in parentheses: -(2(x+3)+x), so:We add all the numbers together, and all the variables
2(x+3)+x
We add all the numbers together, and all the variables
x+2(x+3)
We multiply parentheses
x+2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
-5x-(3x+6)+54=0
We get rid of parentheses
-5x-3x-6+54=0
We add all the numbers together, and all the variables
-8x+48=0
We move all terms containing x to the left, all other terms to the right
-8x=-48
x=-48/-8
x=+6
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