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6/y=5/2y-7
We move all terms to the left:
6/y-(5/2y-7)=0
Domain of the equation: y!=0
y∈R
Domain of the equation: 2y-7)!=0We get rid of parentheses
y∈R
6/y-5/2y+7=0
We calculate fractions
12y/2y^2+(-5y)/2y^2+7=0
We multiply all the terms by the denominator
12y+(-5y)+7*2y^2=0
Wy multiply elements
14y^2+12y+(-5y)=0
We get rid of parentheses
14y^2+12y-5y=0
We add all the numbers together, and all the variables
14y^2+7y=0
a = 14; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·14·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*14}=\frac{-14}{28} =-1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*14}=\frac{0}{28} =0 $
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