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6/x+14=4/3x
We move all terms to the left:
6/x+14-(4/3x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6/x-(+4/3x)+14=0
We get rid of parentheses
6/x-4/3x+14=0
We calculate fractions
18x/3x^2+(-4x)/3x^2+14=0
We multiply all the terms by the denominator
18x+(-4x)+14*3x^2=0
Wy multiply elements
42x^2+18x+(-4x)=0
We get rid of parentheses
42x^2+18x-4x=0
We add all the numbers together, and all the variables
42x^2+14x=0
a = 42; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·42·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*42}=\frac{-28}{84} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*42}=\frac{0}{84} =0 $
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