8(3x+6x+4)=-6x+100

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Solution for 8(3x+6x+4)=-6x+100 equation: 



8(3x+6x+4)=-6x+100

We move all terms to the left:

8(3x+6x+4)-(-6x+100)=0

We add all the numbers together, and all the variables

8(9x+4)-(-6x+100)=0

We multiply parentheses

72x-(-6x+100)+32=0

We get rid of parentheses

72x+6x-100+32=0

We add all the numbers together, and all the variables

78x-68=0

We move all terms containing x to the left, all other terms to the right

78x=68

x=68/78

x=34/39

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