6/7k-3=3/7(4K-7)

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Solution for 6/7k-3=3/7(4K-7) equation: 



6/7k-3=3/7(4-7)

We move all terms to the left:

6/7k-3-(3/7(4-7))=0



Domain of the equation: 7k!=0

k!=0/7

k!=0

k∈R



We add all the numbers together, and all the variables

6/7k-3-(3/7(-3))=0

We calculate fractions


()/(49k^2(-)+(-(3*7k)/(49k^2(-)-3=0

We can not solve this equation

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