4m(m+3)=-32

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Solution for 4m(m+3)=-32 equation: 



4m(m+3)=-32

We move all terms to the left:

4m(m+3)-(-32)=0

We add all the numbers together, and all the variables

4m(m+3)+32=0

We multiply parentheses

4m^2+12m+32=0

a = 4; b = 12; c = +32;
Δ = b2-4ac
Δ = 122-4·4·32
Δ = -368
Delta is less than zero, so there is no solution for the equation

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