6/5(x-4)=1/5(2x-4)

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Solution for 6/5(x-4)=1/5(2x-4) equation: 



6/5(x-4)=1/5(2x-4)

We move all terms to the left:

6/5(x-4)-(1/5(2x-4))=0



Domain of the equation: 5(x-4)!=0

x∈R





Domain of the equation: 5(2x-4))!=0

x∈R



We calculate fractions


(30x2/(5(x-4)*5(2x-4)))+(-5xx/(5(x-4)*5(2x-4)))=0



We calculate terms in parentheses: +(30x2/(5(x-4)*5(2x-4))), so:

30x2/(5(x-4)*5(2x-4))

We multiply all the terms by the denominator


30x2

We add all the numbers together, and all the variables

30x^2

Back to the equation:

+(30x^2)





We calculate terms in parentheses: +(-5xx/(5(x-4)*5(2x-4))), so:

-5xx/(5(x-4)*5(2x-4))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

30x^2-5xx=0

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