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6/2x+8=1/5x+9
We move all terms to the left:
6/2x+8-(1/5x+9)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x+9)!=0We get rid of parentheses
x∈R
6/2x-1/5x-9+8=0
We calculate fractions
30x/10x^2+(-2x)/10x^2-9+8=0
We add all the numbers together, and all the variables
30x/10x^2+(-2x)/10x^2-1=0
We multiply all the terms by the denominator
30x+(-2x)-1*10x^2=0
Wy multiply elements
-10x^2+30x+(-2x)=0
We get rid of parentheses
-10x^2+30x-2x=0
We add all the numbers together, and all the variables
-10x^2+28x=0
a = -10; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-10)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-10}=\frac{-56}{-20} =2+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-10}=\frac{0}{-20} =0 $
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