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X(2X-225)=180
We move all terms to the left:
X(2X-225)-(180)=0
We multiply parentheses
2X^2-225X-180=0
a = 2; b = -225; c = -180;
Δ = b2-4ac
Δ = -2252-4·2·(-180)
Δ = 52065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52065}=\sqrt{9*5785}=\sqrt{9}*\sqrt{5785}=3\sqrt{5785}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-3\sqrt{5785}}{2*2}=\frac{225-3\sqrt{5785}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+3\sqrt{5785}}{2*2}=\frac{225+3\sqrt{5785}}{4} $
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