6-x=4(x-3)+x-4

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Solution for 6-x=4(x-3)+x-4 equation: 



6-x=4(x-3)+x-4

We move all terms to the left:

6-x-(4(x-3)+x-4)=0

We add all the numbers together, and all the variables

-1x-(4(x-3)+x-4)+6=0



We calculate terms in parentheses: -(4(x-3)+x-4), so:

4(x-3)+x-4

We add all the numbers together, and all the variables

x+4(x-3)-4

We multiply parentheses

x+4x-12-4

We add all the numbers together, and all the variables

5x-16

Back to the equation:

-(5x-16)



We get rid of parentheses

-1x-5x+16+6=0

We add all the numbers together, and all the variables

-6x+22=0

We move all terms containing x to the left, all other terms to the right

-6x=-22

x=-22/-6

x=3+2/3

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