2(100-y)+4y=306

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Solution for 2(100-y)+4y=306 equation: 



2(100-y)+4y=306

We move all terms to the left:

2(100-y)+4y-(306)=0

We add all the numbers together, and all the variables

2(-1y+100)+4y-306=0

We add all the numbers together, and all the variables

4y+2(-1y+100)-306=0

We multiply parentheses

4y-2y+200-306=0

We add all the numbers together, and all the variables

2y-106=0

We move all terms containing y to the left, all other terms to the right

2y=106

y=106/2

y=53

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