6-x+6-x+6-x+6-x=2(x+1)+2(x+1)+x+x

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Solution for 6-x+6-x+6-x+6-x=2(x+1)+2(x+1)+x+x equation:



6-x+6-x+6-x+6-x=2(x+1)+2(x+1)+x+x
We move all terms to the left:
6-x+6-x+6-x+6-x-(2(x+1)+2(x+1)+x+x)=0
We add all the numbers together, and all the variables
-4x-(2(x+1)+2(x+1)+x+x)+24=0
We calculate terms in parentheses: -(2(x+1)+2(x+1)+x+x), so:
2(x+1)+2(x+1)+x+x
We add all the numbers together, and all the variables
2x+2(x+1)+2(x+1)
We multiply parentheses
2x+2x+2x+2+2
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
We get rid of parentheses
-4x-6x-4+24=0
We add all the numbers together, and all the variables
-10x+20=0
We move all terms containing x to the left, all other terms to the right
-10x=-20
x=-20/-10
x=+2

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