((X-2)/5)+1=(2x+1)/2

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Solution for ((X-2)/5)+1=(2x+1)/2 equation: 



((X-2)/5)+1=(2X+1)/2

We move all terms to the left:

((X-2)/5)+1-((2X+1)/2)=0

We calculate fractions


(2X-4)/()+(-10X-5)/()+1=0

We multiply all the terms by the denominator


(2X-4)+(-10X-5)+1*()=0

We add all the numbers together, and all the variables

(2X-4)+(-10X-5)=0

We get rid of parentheses

2X-10X-4-5=0

We add all the numbers together, and all the variables

-8X-9=0

We move all terms containing X to the left, all other terms to the right

-8X=9

X=9/-8

X=-1+1/8

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