6-8(b+2)=-10-8b

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Solution for 6-8(b+2)=-10-8b equation: 



6-8(b+2)=-10-8b

We move all terms to the left:

6-8(b+2)-(-10-8b)=0

We add all the numbers together, and all the variables

-8(b+2)-(-8b-10)+6=0

We multiply parentheses

-8b-(-8b-10)-16+6=0

We get rid of parentheses

-8b+8b+10-16+6=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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