1/3(2x-1)=3/2(x+4)

Solution for 1/3(2x-1)=3/2(x+4) equation:

1/3(2x-1)=3/2(x+4)

We move all terms to the left:

1/3(2x-1)-(3/2(x+4))=0


Domain of the equation: 3(2x-1)!=0

x∈R



Domain of the equation: 2(x+4))!=0

x∈R


We calculate fractions


(2xx/(3(2x-1)*2(x+4)))+(-9x2/(3(2x-1)*2(x+4)))=0


We calculate terms in parentheses: +(2xx/(3(2x-1)*2(x+4))), so:

2xx/(3(2x-1)*2(x+4))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)



We calculate terms in parentheses: +(-9x2/(3(2x-1)*2(x+4))), so:

-9x2/(3(2x-1)*2(x+4))

We multiply all the terms by the denominator


-9x2

We add all the numbers together, and all the variables

-9x^2

Back to the equation:

+(-9x^2)


We get rid of parentheses

-9x^2+2xx=0