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6-5b/3b-12=3
We move all terms to the left:
6-5b/3b-12-(3)=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
-5b/3b-9=0
We multiply all the terms by the denominator
-5b-9*3b=0
Wy multiply elements
-5b-27b=0
We add all the numbers together, and all the variables
-32b=0
b=0/-32
b=0
Równanie nie ma rozwiązania
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