(2n-3)/3+2n=5

Solution for (2n-3)/3+2n=5 equation:

(2n-3)/3+2n=5

We move all terms to the left:

(2n-3)/3+2n-(5)=0

We add all the numbers together, and all the variables

2n+(2n-3)/3-5=0

We multiply all the terms by the denominator


2n*3+(2n-3)-5*3=0

We add all the numbers together, and all the variables

2n*3+(2n-3)-15=0

Wy multiply elements

6n+(2n-3)-15=0

We get rid of parentheses

6n+2n-3-15=0

We add all the numbers together, and all the variables

8n-18=0

We move all terms containing n to the left, all other terms to the right

8n=18

n=18/8

n=2+1/4