6-5(3x-2)-(x+20)=28

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Solution for 6-5(3x-2)-(x+20)=28 equation: 



6-5(3x-2)-(x+20)=28

We move all terms to the left:

6-5(3x-2)-(x+20)-(28)=0

We add all the numbers together, and all the variables

-5(3x-2)-(x+20)-22=0

We multiply parentheses

-15x-(x+20)+10-22=0

We get rid of parentheses

-15x-x-20+10-22=0

We add all the numbers together, and all the variables

-16x-32=0

We move all terms containing x to the left, all other terms to the right

-16x=32

x=32/-16

x=-2

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