3k+2(k+1)=10k-5(k+4)

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Solution for 3k+2(k+1)=10k-5(k+4) equation: 



3k+2(k+1)=10k-5(k+4)

We move all terms to the left:

3k+2(k+1)-(10k-5(k+4))=0

We multiply parentheses

3k+2k-(10k-5(k+4))+2=0



We calculate terms in parentheses: -(10k-5(k+4)), so:

10k-5(k+4)

We multiply parentheses

10k-5k-20

We add all the numbers together, and all the variables

5k-20

Back to the equation:

-(5k-20)



We add all the numbers together, and all the variables

5k-(5k-20)+2=0

We get rid of parentheses

5k-5k+20+2=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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